LEGRAND 0 281 94 Manual página 5

e d
a r g
c h
d is
12 Ir
t= k@
2
I 0.2
0.3
tm
0.3
s
Im 6
0.0
FF
=O
M EM
xI r
10
tr
12
Ii 6
s
8 0.1
xI n 0.0 @ 6I r
Ic w
2
4 xI n
0.0
0. 9 2
0. 8 0.0
0
Ir 0.0
0. 6
N
0. 5
0. 4
x Ir
O N
0
I> .9
05
I> 1.
discharged
Im
1 2
Ii 6
0. 08
x In
Ic w
2
e d
a r g
c h
Ir
12
2 t= k@
I
0.3 0.2
tm
0.3
s
6
Im
0.0 FF
=O
M EM
xI r
tr 10
12
Ii 6
s
xI n 0.0 8 0.1 r
@ 6I
Ic w
2
0.0 4 xI n
0. 9
0. 8 2
0.0 0
Ir 0.0
0. 6
N
0. 5
0. 4
x Ir
O N
I> .9 0
I> 1. 05
e d
a r g
c h
1 2 Ir
t= k@
2
I 0. 2
0. 3
tm
0. 3
s
6
0. 0
FF
= O
M EM
x Ir
1 0
tr
s
0. 1
@ 6 Ir
13
Ir
12
t= k@
2 I 0. 2
0. 3
tm
0. 3
s
Im 6
0. 0
FF
=O
M EM
xI r
tr 10
12
Ii 6
s
0. 08 0. 1
xI n @ 6I r
Ic w
2
0. 04 xI n
0. 9
0. 8 0. 02
Ir 0. 00
0. 6
N
0. 5
0. 4
x Ir
O N
I> .9 0
I> 1. 05
charged
discharged
5
e d
a r g
c h
charged
14