Publicidad
EL-520W
CALCULATION EXAMPLES
ANWENDUNGSBEISPIELE
EXEMPLES DE CALCUL
EJEMPLOS DE CÁLCULO
EXEMPLOS DE CÁLCULO
ESEMPI DI CALCOLO
REKENVOORBEELDEN
PÉLDASZÁMÍTÁSOK
PŘÍKLADY VÝPOČTŮ
RÄKNEEXEMPEL
LASKENTAESIMERKKEJÄ
èêàåÖêõ ÇõóàëãÖçàâ
UDREGNINGSEKSEMPLER
CONTOH-CONTOH PENGHITUNGAN
CONTOH-CONTOH PERHITUNGAN
[]
ª 3 ( 5 + 2 )=
13(5+2)=
3 * 5 + 2 =
23×5+2=
3 * 5 + 3 * 2 =
33×5+3×2=
→1
@[
→2
]
→3
]
→2
[
"
100000÷3=
ª 100000 / 3 =
[NORM1]
→[FIX]
"10
"2 2
[TAB 2]
→[SCI]
"11
→[ENG]
"12
→[NORM1]
"13
3÷1000=
ª 3 / 1000 =
[NORM1]
→[NORM2]
"14
→[NORM1]
"13
+-*/()±E
ª 45 + 285 / 3 =
45+285÷3=
( 18 + 6 )/
18+6
=
( 15 - 8 =
15–8
42 *± 5 + 120 =
42×(–5)+120=
(5 ±)
*
1
*
1
)= 5 E 3 / 4 E
(5×10
3
)÷(4×10
–3
± 3 =
34 + 57 =
34+57=
+ 57
=
45+57=
45
68 * 25 =
68×25=
68 *
40 =
68×40=
sutSUTVhH
Ile¡•L÷⁄™
$#!qQ%
ªs 60 =
sin60[°]=
π
"01u(
cos — [rad]=
@V/ 4 )=
4
"02@T 1 =
tan
–1
1=[g]
"00
• • • •
• • • •
(cosh 1.5 +
sinh 1.5)
2
=
5
tanh
–1
— =
7
ln 20 =
log 50 =
e
3
=
10
1.7
=
1
1
— + — =
6
7
× 5
8
–2
– 3
4
2
=
1
—
(12
3
)
=
4
8
3
¿49 –
¿81 =
4
¿27
3
4! =
P
=
10
3
C
=
5
2
500×25%=
120÷400=?%
500+(500×25%)= 500 + 25 @%
21.
400–(400×30%)= 400 - 30 @%
17.
21.
•
21.
•
17.
•
21.
•
17.
•
•
•
•
•
33'333.33333
•
33'333.33333
•
33'333.33
•
3.33 × 10
04–
•
33.33 × 10
03–
•
33'333.33333
•
•
0.003
•
3. × 10
–03
•
0.003
DEG
RAD
140.
GRAD
3.428571429
–90.
Åè
d/dx (x
4
– 0.5x
3
+ 6x
x=2
1'250'000.
dx=0.00002
x=3
dx=0.001
8
∫
(x
2
– 5)dx
2
91.
n=100
102.
n=10
1'700.
2'720.
g
90°→ [rad]
→ [g]
→ [°]
sin
–1
0.8 = [°]
0.866025403
→ [rad]
→ [g]
→ [°]
0.707106781
50.
ª(hu 1.5 +h
s 1.5 )L=
20.08553692
@Ht( 5
/ 7 )=
0.895879734
I 20 =
2.995732274
l 50 =
1.698970004
@e 3 =
20.08553692
@¡ 1.7 =
50.11872336
6 @•+ 7 @
•=
0.309523809
8 ™± 2 - 3 ™
4 * 5 L=
–2'024.984375
12 ™ 3 ™ 4
@•=
6.447419591
8 ÷=
@⁄ 49 - 4 @$
81 =
@# 27 =
4 @!=
10 @q 3 =
5 @Q 2 =
500 * 25 @%
120 / 400 @%
θ = sin
x , θ = tan
θ = cos
–1
–1
x
–1
–90 ≤ θ ≤ 90
0 ≤ θ ≤ 180
π
π
– — ≤ θ ≤ —
0 ≤ θ ≤ π
2
2
–100 ≤ θ ≤ 100
0 ≤ θ ≤ 200
) ªKˆ™ 4 - 0.5 K
2
ˆ÷+ 6 KˆL
@Å 2 ®®
® 3 ® 0.001 ®
130.5000029
ªKˆL- 5
è 2 ® 8 ®®
®®® 10 ®
ª 90 @g
1.570796327
@g
@g
@S 0.8 =
53.13010235
@g
0.927295218
@g
59.03344706
@g
53.13010235
KRO;:?≥∆˚¬
ª 8 * 2 OM
24 /KM=
24÷(8×2)=
KM* 5 =
(8×2)×5=
ªOM
150 * 3 ;
$150×3:M
1
250 ;
+)$250:M
=M
+250
2
1
×5%
RM* 5 @%
–)M
2
@:RM
M
110 OY
$1=¥110
26510 /RY=
¥26,510=$?
2750 *RY=
$2,750=¥?
3 OY
r=3cm (r→Y)
πr
@VKYL=
2
=?
24
24 /( 4 + 6 )=
—— = 2.4...(A)
4+6
3 *K?+ 60 /
3×(A)+60÷(A)=
512.
K?=
πr
⇒F1
@VKYL
2
4.
O≥
3.
3 OY
4
R≥* 4 / 3 =
V = ?
3
24.
720.
10.
ª 6 + 4 =
125.
6+4=ANS
+ 5 =
ANS+5
30.
8 * 2 =
8×2=ANS
625.
L=
ANS
2
280.
44 + 37 =
44+37=ANS
√ANS=
@⁄=
\|
1
4
b
ª 3 \ 1 \ 2 +
3— + — = [a—]
c
2
3
4 \ 3 =
→[a.xxx]
\
→[d/c]
@|
2
—
@¡ 2 \ 3 =
=
10
3
5
(
7
)
7 \ 5 ™ 5 =
—
=
5
1 \ 8 ™ 1 \ 3
1
1
(
)
—
—
=
3
=
8
64
@⁄ 64 \ 225 =
—— =
225
( 2 ™ 3 ) \
2
3
— =
( 3 ™ 4 ) =
3
4
1.2
1.2 \ 2.3 =
—– =
x
2.3
1°2'3"
——– =
1 o 2 o 3 \ 2 =
2
1×10
3
——– =
1 E 3 \ 2 E 3 =
2×10
3
ª 7 OA
A = 7
4
4 \KA=
— =
A
2
1.25 + 2 \ 5 =
1.25 + — = [a.xxx]
5
b
→[a—]
\
c
50.
5
* 4
5
6 = 4—
l
l
6
êûîìíãâ†ä
àá
138.
138.
ª@í 25 @ê
DEC(25)→BIN
@ì 1AC
HEX(1AC)
→BIN
@ê
→PEN
@û
→OCT
@î
100.
→DEC
@í
90.
@ê( 1010 - 100 )
BIN(1010–100)
×11 =
* 11 =
ã 111 =
BIN(111)→NEG
@ì 1FF @î+
HEX(1FF)+
512 =
OCT(512)=
@ì
HEX(?)
• • • •
16.
1.5
80.
0.
450.
250.
35.
665.
110.
241.
302'500.
3.
28.27433388
2.4
32.2
F1
3.
37.69911184
10.
15.
16.
256.
81.
9.
4
5
6 *
l
l
4.833333333
29
6
l
4.641588834
16807
3125
l
1
2
l
8
15
l
8
81
l
12
23
l
0°31'1.5"
1
2
l
7.
4
7
l
1.65
1
13
20
l
l
11001.
b
110101100.
b
3203.
P
654.
0
428.
10010.
b
1111111001.
b
1511.
0
349.
H
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