Adjusting The Boom Gate - Nice M-BAR Serie Instrucciones Y Advertencias Para La Instalación Y El Uso

3.6 ADJUSTING THE BOOM GATE

The boom gate is factory-set in the following way:
– balancing spring fastened to the right, installation selector on
the right, anchored through non-permanent holes
– closing manoeuvre of the boom towards the left.
These are random settings, therefore the following checks must
be carried out to understand whether they must be changed:
– if a single accessory will be installed: identify in box "A"
in "Figure 6" your boom gate version, the length of the boom
and, lastly, the accessory you intend mounting on the boom;
with this data, read the corresponding letter and the number
relative to the holes to be chosen to attach the spring
6
M3BAR / M5BAR
C B A A B C
M7BAR / L9BAR
B A A B
3 2 1 1 2 3
Add the numbers between
1.
brackets, present
column, choosing
among those linked to the
installed accessories.
Use the result of the addition
2.
to determine the number of
holes required to attach the
spring.
56 – ENGLISH
A
M3BAR
M3BAR
? 2,65 m
XBA15
(3,15 m) – 0,50m
XBA13
A
1
XBA13
A
1
XBA4 /
XBA6 / XBA18
XBA11
B
3
B
M5BAR
M5BAR
? 3,50 m
XBA14
(4,15 m) – 0,65 m
XBA13
(0)
XBA13
(1)
XBA4 /
XBA6 / XBA18
WA13
(1)
WA12
(5)
in the
B
only
0 ÷ 1 = 0 ÷ 1 =
2
B
2 ÷ 7 = 2 ÷ 4 =
3
5 ÷ 6 =
– if multiple accessories will be installed: identify in box "B"
in "Figure 6" your boom gate version, the length of the boom
and, lastly, the type and number of accessories you wish to
mount on the boom; add the numbers in brackets linked to the
accessories and use the result of the addition to read, in the
lower part of box "B", the letter and the number relative to the
holes to be chosen to attach the spring
– if the boom must close tot he right of the motor: the spring's
attachment must be shifted to one of the holes located on the
other arm of the balancing lever.
M5BAR
M5BAR
3,15 m 3,50 m 4,15 m
XBA15 XBA14 XBA14
(3,15 m) (4,15m) – 0,65 m (4,15m)
A B B
3 2 3
A B B
3 2 3
B C C
3 1 3
4,15 m 5,15 m 5,15 m
XBA14 XBA5 XBA5 XBA15+XBA15
(4,15m) (5,15m) (5,15m) (6,30 m) – 1,30m
(0) (0) (0)
(1) (1) (1)
(1) - (2)
(4) (4) (4)
B C A
4 ÷ 5 = 0 ÷ 2 = 0 ÷ 2 =
3 2 2
C A
3 ÷ 5 = 3 ÷ 5 =
1 2
C A
6 ÷ 7 =
2 3
M7BAR L9BAR
M7BAR L9BAR
5,15 m 7,33 m 9,33 m
XBA5 XBA15 XBA14
(5,15m) + XBA14 + XBA5
C B B
2 2 1
C B B
2 2 1
M7BAR
M7BAR
5,00 m 6,33 m 7,33 m
XBA15 XBA15
+ XBA15 + XBA14
(0) (0) (0)
(1) (1) (1)
(1) (1) -
(3) (3) (3)
B B B
0 ÷ 2 = 3 ÷ 4 = 0 ÷ 2 =
1 1 3
B B
3 ÷ 5 = 3 ÷ 4 =
2 2
5 ÷ 6 =
L9BAR
L9BAR
7,33 m 8,33 m
XBA15 XBA14
+ XBA14 + XBA14
(0) (0)
(1) (1)
(2) (2)
(3) (3)
A A
0 ÷ 2 =
1 3
A B
3 ÷ 6 =
2 1
A
3